Jawahar Navodaya Examination Preparation 2026

  Question: A park is 1500 m long and 750 m wide. A cyclist has to take four rounds of this park. How much time will he take at a speed of 4.5 km/h? Options: (a) 40 h (b) 20 h (c) 10 h (d) 4 h Step 1: Understanding the Problem Like a Kid Imagine a big rectangle-shaped park. The cyclist rides around the park’s boundary — that’s like walking along the edge of a chocolate bar. To find out how far he will ride , we need the perimeter of the park. Formula for perimeter of a rectangle: Perimeter = 2 × ( Length + Width ) \text{Perimeter} = 2 \times (\text{Length} + \text{Width}) Perimeter = 2 × ( Length + Width ) Here: Length = 1500 m Width = 750 m So, Perimeter = 2 × ( 1500 + 750 ) = 2 × 2250 = 4500  m \text{Perimeter} = 2 \times (1500 + 750) = 2 \times 2250 = 4500 \text{ m} Perimeter = 2 × ( 1500 + 750 ) = 2 × 2250 = 4500  m Think of it like: if you walk around the edge of your school 2 times (like 2 rectangles stuck together), you know the total path. ...

  Question 51: Find the approximate result of the expression (in whole numbers): 49.6 × 10.2 − 7.1 × 29.7 − 5.1 × 20.1 49.6 \times 10.2 - 7.1 \times 29.7 - 5.1 \times 20.1 49.6 × 10.2 − 7.1 × 29.7 − 5.1 × 20.1 Options: (a) 390 (b) 290 (c) 209 (d) 190 Step 1: Round the numbers for approximation 49.6 ≈ 50 49.6 \approx 50 49.6 ≈ 50 , 10.2 ≈ 10 10.2 \approx 10 10.2 ≈ 10 → 50 × 10 = 500 50 \times 10 = 500 50 × 10 = 500 7.1 ≈ 7 7.1 \approx 7 7.1 ≈ 7 , 29.7 ≈ 30 29.7 \approx 30 29.7 ≈ 30 → 7 × 30 = 210 7 \times 30 = 210 7 × 30 = 210 5.1 ≈ 5 5.1 \approx 5 5.1 ≈ 5 , 20.1 ≈ 20 20.1 \approx 20 20.1 ≈ 20 → 5 × 20 = 100 5 \times 20 = 100 5 × 20 = 100 Step 2: Perform the calculation 500 − 210 − 100 = 190 500 - 210 - 100 = 190 500 − 210 − 100 = 190 ✅ Answer: (d) 190 Tip for fast calculation: Round off numbers to the nearest whole number before multiplying. Do step-by-step subtraction after approximation. This gives a quick and reasonably accurate result for multipl...

  Question 50: 5% of 10% of 175 grams is equal to: (a) 8.75 gm (b) 0.5 gm (c) 0.875 gm (d) 17.5 gm Step 1: Find 10% of 175 10 %  of  175 = 0.1 × 175 = 17.5   grams 10\% \text{ of } 175 = 0.1 \times 175 = 17.5 \, \text{grams} 10%  of  175 = 0.1 × 175 = 17.5 grams Step 2: Find 5% of 17.5 5 %  of  17.5 = 0.05 × 17.5 = 0.875   grams 5\% \text{ of } 17.5 = 0.05 \times 17.5 = 0.875 \, \text{grams} 5%  of  17.5 = 0.05 × 17.5 = 0.875 grams ✅ Answer: (c) 0.875 gm Tip for fast calculation: Convert percentages to decimals and multiply step by step: 5 %  of  10 % = 0.05 × 0.1 = 0.005 5\% \text{ of } 10\% = 0.05 \times 0.1 = 0.005 5%  of  10% = 0.05 × 0.1 = 0.005 0.005 × 175 = 0.875 0.005 \times 175 = 0.875 0.005 × 175 = 0.875 This avoids multiple small steps and reduces errors.

  Question 49: If the number B B B is 10% less than another number C C C and C C C is 5% more than 150, then B B B is equal to: (a) 157.85 (b) 153.85 (c) 151.75 (d) 141.75 Step 1: Find C C = 150 + 5 %  of  150 = 150 + 7.5 = 157.5 C = 150 + 5\% \text{ of } 150 = 150 + 7.5 = 157.5 C = 150 + 5%  of  150 = 150 + 7.5 = 157.5 Step 2: Find B (10% less than C) B = C − 10 %  of  C = 157.5 − 15.75 = 141.75 B = C - 10\% \text{ of } C = 157.5 - 15.75 = 141.75 B = C − 10%  of  C = 157.5 − 15.75 = 141.75 ✅ Answer: (d) 141.75 Tip for fast calculation: Quickly find percentages using decimal form: 5 %  of 150 = 0.05 × 150 = 7.5 5\% \text{ of 150} = 0.05 \times 150 = 7.5 5%  of 150 = 0.05 × 150 = 7.5 10 %  of 157.5 = 0.1 × 157.5 = 15.75 10\% \text{ of 157.5} = 0.1 \times 157.5 = 15.75 10%  of 157.5 = 0.1 × 157.5 = 15.75 Subtract/add directly to get the final number.

  Question 48: The value of 0.9 ÷ ( 0.3 × 0.3 ) 0.9 \div (0.3 \times 0.3) 0.9 ÷ ( 0.3 × 0.3 ) is: (a) 0.01 (b) 0.1 (c) 1 (d) 10 Step 1: Solve inside the bracket first 0.3 × 0.3 = 0.09 0.3 \times 0.3 = 0.09 0.3 × 0.3 = 0.09 Step 2: Divide 0.9 by 0.09 0.9 ÷ 0.09 = 10 0.9 \div 0.09 = 10 0.9 ÷ 0.09 = 10 ✅ Answer: (d) 10 Tip for fast calculation: Convert decimals to whole numbers by multiplying numerator and denominator by 100: 0.9 ÷ 0.09 = 90 ÷ 9 = 10 0.9 \div 0.09 = 90 \div 9 = 10 0.9 ÷ 0.09 = 90 ÷ 9 = 10 This avoids small decimal division mistakes.

  🧮 JNVST BODMAS Practice Sheet – Top 20 Questions Instructions: Solve using BODMAS rules. Division/Multiplication and Addition/Subtraction are left-to-right. Questions 15 − 15 ÷ 15 × 6 = ? 15 - 15 \div 15 \times 6 = ? 15 − 15 ÷ 15 × 6 = ? 50 ÷ 5 × 2 + 3 = ? 50 \div 5 \times 2 + 3 = ? 50 ÷ 5 × 2 + 3 = ? 100 − 20 × 3 ÷ 5 = ? 100 - 20 \times 3 \div 5 = ? 100 − 20 × 3 ÷ 5 = ? ( 8 + 2 ) × 5 ÷ 2 = ? (8 + 2) \times 5 \div 2 = ? ( 8 + 2 ) × 5 ÷ 2 = ? 45 ÷ 5 + 6 × 2 − 3 = ? 45 \div 5 + 6 \times 2 - 3 = ? 45 ÷ 5 + 6 × 2 − 3 = ? 36 ÷ ( 6 + 6 ) × 4 = ? 36 \div (6 + 6) \times 4 = ? 36 ÷ ( 6 + 6 ) × 4 = ? 7 + 3 × 6 − 8 ÷ 4 = ? 7 + 3 \times 6 - 8 \div 4 = ? 7 + 3 × 6 − 8 ÷ 4 = ? ( 18 − 6 ) ÷ 2 + 5 × 3 = ? (18 - 6) \div 2 + 5 \times 3 = ? ( 18 − 6 ) ÷ 2 + 5 × 3 = ? 20 ÷ 4 + 12 ÷ 3 × 2 = ? 20 \div 4 + 12 \div 3 \times 2 = ? 20 ÷ 4 + 12 ÷ 3 × 2 = ? 100 − ( 25 × 2 ) + 30 ÷ 5 = ? 100 - (25 \times 2) + 30 \div 5 = ? 100 − ( 25 × 2 ) + 30 ÷ 5 = ? 12 × 2 ÷ 3 + 7 − ...

  🧮 BODMAS Cheat Sheet for Quick Calculations BODMAS = Brackets, Orders (powers, roots), Division, Multiplication, Addition, Subtraction Step-by-Step Rules Brackets first – solve anything inside ( ) Orders next – powers, squares, square roots Division & Multiplication – from left to right Addition & Subtraction – from left to right Tip: Multiplication/division or addition/subtraction are done in the order they appear , not always multiplication first. Quick Examples 1️⃣ 15 - 15 ÷ 15 × 6 Division: 15 ÷ 15 = 1 Multiplication: 1 × 6 = 6 Subtraction: 15 - 6 = 9 ✅ 2️⃣ 50 ÷ 5 × 2 + 3 Division: 50 ÷ 5 = 10 Multiplication: 10 × 2 = 20 Addition: 20 + 3 = 23 ✅ 3️⃣ 100 - 20 × 3 ÷ 5 Multiplication: 20 × 3 = 60 Division: 60 ÷ 5 = 12 Subtraction: 100 - 12 = 88 ✅ 4️⃣ (8 + 2) × 5 ÷ 2 Brackets: 8 + 2 = 10 Multiplication: 10 × 5 = 50 Division: 50 ÷ 2 = 25 ✅ 5️⃣ 45 ÷ 5 + 6 × 2 - 3 Division: 45 ÷ 5 = 9 Multiplicati...